C 程序比较两个矩阵是否相等
cserver side programmingprogramming更新于 2024/11/3 5:42:00
用户必须输入两个矩阵的顺序和两个矩阵的元素。然后，比较这两个矩阵。
如果矩阵元素和大小都相等，则显示两个矩阵相等。
如果矩阵大小相等但元素不相等，则显示矩阵可以比较但不相等。
如果大小和元素不匹配，则显示矩阵无法比较。
程序
以下是 C 程序，用于比较两个矩阵是否相等 −
#include <stdio.h>
#include <conio.h>
main(){
int A[10][10], B[10][10];
int i, j, R1, C1, R2, C2, flag =1;
printf("Enter the order of the matrix A
");
scanf("%d %d", &R1, &C1);
printf("Enter the order of the matrix B
");
scanf("%d %d", &R2,&C2);
printf("Enter the elements of matrix A
");
for(i=0; i<R1; i++){
for(j=0; j<C1; j++){
scanf("%d",&A[i][j]);
}
}
printf("Enter the elements of matrix B
");
for(i=0; i<R2; i++){
for(j=0; j<C2; j++){
scanf("%d",&B[i][j]);
}
}
printf("MATRIX A is
");
for(i=0; i<R1; i++){
for(j=0; j<C1; j++){
printf("%3d",A[i][j]);
}
printf("
");
}
printf("MATRIX B is
");
for(i=0; i<R2; i++){
for(j=0; j<C2; j++){
printf("%3d",B[i][j]);
}
printf("
");
}
/* Comparing two matrices for equality */
if(R1 == R2 && C1 == C2){
printf("Matrices can be compared
");
for(i=0; i<R1; i++){
for(j=0; j<C2; j++){
if(A[i][j] != B[i][j]){
flag = 0;
break;
}
}
}
}
else{
printf(" Cannot be compared
");
exit(1);
}
if(flag == 1 )
printf("Two matrices are equal
");
else
printf("But,two matrices are not equal
");
}
输出
当执行上述程序时，它会产生以下结果 −
Run 1: Enter the order of the matrix A 2 2 Enter the order of the matrix B 2 2 Enter the elements of matrix A 1 2 3 4 Enter the elements of matrix B 1 2 3 4 MATRIX A is 1 2 3 4 MATRIX B is 1 2 3 4 Matrices can be compared Two matrices are equal Run 2: Enter the order of the matrix A 2 2 Enter the order of the matrix B 2 2 Enter the elements of matrix A 1 2 3 4 Enter the elements of matrix B 5 6 7 8 MATRIX A is 1 2 3 4 MATRIX B is 5 6 7 8 Matrices can be compared But,two matrices are not equal
