在 MYSQL 中获取成绩公布日期早于当前日期 12 天的学生记录
mysqlmysqli database更新于 2024/2/6 11:59:00
为此，您需要比较并找出当前日期与学生成绩日期之间的差异。这可以使用 AND 运算符和 DATEDIFF() 来完成。
首先我们创建一个表 −
mysql> create table DemoTable1547 -> ( -> StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> StudentName varchar(20), -> StudentMarks int, -> StudentResultDeclareDate datetime -> ); Query OK, 0 rows affected (0.55 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable1547(StudentName,StudentMarks,StudentResultDeclareDate) values('Chris',56,'2019-10-13 13:00:00')
-> ;
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable1547(StudentName,StudentMarks,StudentResultDeclareDate) values('Bob',60,'2019-10-13 12:00:00');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable1547(StudentName,StudentMarks,StudentResultDeclareDate) values('Mike',45,'2019-10-13 14:00:00');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable1547(StudentName,StudentMarks,StudentResultDeclareDate) values('Carol',78,'2019-10-01 14:00:00');
Query OK, 1 row affected (0.11 sec)
使用 select 语句显示表中的所有记录 −
mysql> select * from DemoTable1547;
这将产生以下输出 −
+-----------+-------------+--------------+--------------------------+ | StudentId | StudentName | StudentMarks | StudentResultDeclareDate | +-----------+-------------+--------------+--------------------------+ | 1 | Chris | 56 | 2019-10-13 13:00:00 | | 2 | Bob | 60 | 2019-10-13 12:00:00 | | 3 | Mike | 45 | 2019-10-13 14:00:00 | | 4 | Carol | 78 | 2019-10-01 14:00:00 | +-----------+-------------+--------------+--------------------------+ 4 rows in set (0.00 sec)
当前日期如下 −
mysql> select curdate(); +------------+ | curdate() | +------------+ | 2019-10-13 | +------------+ 1 row in set (0.00 sec)
以下查询用于获取成绩在当前日期前 12 天公布的学生记录 −
mysql> select * from DemoTable1547 where datediff(curdate(),StudentResultDeclareDate) >=12 and StudentMarks > 50;
这将产生以下输出 −
+-----------+-------------+--------------+--------------------------+ | StudentId | StudentName | StudentMarks | StudentResultDeclareDate | +-----------+-------------+--------------+--------------------------+ | 4 | Carol | 7 8 | 2019-10-01 14:00:00 | +-----------+-------------+--------------+--------------------------+ 1 row in set (0.00 sec)
