如何在 MySQL 中获取当前日期前两天的记录?
mysqlmysqli database更新于 2023/12/18 21:23:00
要获取当前日期前几天的记录，您需要使用 DATE_SUB()。我们还将使用 NOW() 来获取当前日期。其语法如下
SELECT *FROM yourTableName WHERE yourDateTimeColumnName BETWEEN DATE_SUB(DATE(NOW()), INTERVAL 2 DAY) AND DATE_SUB(DATE(NOW()), INTERVAL 1 DAY);
Let us see an example
mysql> create table get2daysAgoDemo - > ( - > Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, - > Name varchar(20), - > PostDateTime datetime - > ); Query OK, 0 rows affected (1.70 sec)
使用 insert 命令在表中插入一些记录。
查询如下
mysql> insert into get2daysAgoDemo(Name,PostDateTime) values('Larry',now());
Query OK, 1 row affected (0.68 sec)
mysql> insert into get2daysAgoDemo(Name,PostDateTime) values('Mike','2019-02-13');
Query OK, 1 row affected (0.12 sec)
mysql> insert into get2daysAgoDemo(Name,PostDateTime) values('Sam','2019-01-31');
Query OK, 1 row affected (0.15 sec)
mysql> insert into get2daysAgoDemo(Name,PostDateTime) values('Bob','2019-02-14');
Query OK, 1 row affected (0.29 sec)
mysql> insert into get2daysAgoDemo(Name,PostDateTime) values('David','2019-02-12');
Query OK, 1 row affected (0.21 sec)
mysql> insert into get2daysAgoDemo(Name,PostDateTime) values('Carol','2019-02-11');
Query OK, 1 row affected (0.22 sec)
使用 select 语句显示表中的所有记录。
查询如下
mysql> select *from get2daysAgoDemo;
以下是输出 −
+----+-------+---------------------+ | Id | Name | PostDateTime | +----+-------+---------------------+ | 1 | Larry | 2019-02-15 21:47:10 | | 2 | Mike | 2019-02-13 00:00:00 | | 3 | Sam | 2019-01-31 00:00:00 | | 4 | Bob | 2019-02-14 00:00:00 | | 5 | David | 2019-02-12 00:00:00 | | 6 | Carol | 2019-02-11 00:00:00 | +----+-------+---------------------+ 6 rows in set (0.00 sec)
以下是获取过去两天记录的查询。假设当前日期为 2019-02-15
mysql> select *from get2daysAgoDemo - > where PostDateTime between DATE_SUB(DATE(NOW()), INTERVAL 2 DAY) - > AND DATE_SUB(DATE(NOW()), INTERVAL 1 DAY);
以下是显示过去两天(即 2 月 13 日和 14 日)记录的输出，因为我们的当前日期是 2 月 15 日
+----+------+---------------------+ | Id | Name | PostDateTime | +----+------+---------------------+ | 2 | Mike | 2019-02-13 00:00:00 | | 4 | Bob | 2019-02-14 00:00:00 | +----+------+---------------------+ 2 rows in set (0.01 sec)
