如果条件满足，则在 MySQL 中选择一列，从当前日期和当前日期 + 1 中获取记录
mysqlmysqli database更新于 2023/12/30 18:21:00
让我们首先获取当前日期 −
mysql> select curdate();
这将产生以下输出 −
+------------+ | curdate() | +------------+ | 2019-12-15 | +------------+ 1 row in set (0.00 sec)
首先我们创建一个表 −
mysql> create table DemoTable1956 ( ProductId int, ProductName varchar(20), CustomerName varchar(20), ShippingDate date ); Query OK, 0 rows affected (0.00 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable1956 values(101,'Product-1','Sam','2019-10-11'); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1956 values(102,'Product-2','Carol','2018-12-01'); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1956 values(103,'Product-3','David','2019-12-15'); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1956 values(104,'Product-4','Robert','2019-12-16'); Query OK, 1 row affected (0.00 sec)
使用 select 语句显示表中的所有记录 −
mysql> select * from DemoTable1956;
这将产生以下输出 −
+-----------+-------------+--------------+--------------+ | ProductId | ProductName | CustomerName | ShippingDate | +-----------+-------------+--------------+--------------+ | 101 | Product-1 | Sam | 2019-10-11 | | 102 | Product-2 | Carol | 2018-12-01 | | 103 | Product-3 | David | 2019-12-15 | | 104 | Product-4 | Robert | 2019-12-16 | +-----------+-------------+--------------+--------------+ 4 rows in set (0.00 sec)
以下查询用于选择一列并获取当前日期和下一个日期的记录 −
mysql> select CustomerName from DemoTable1956 where ShippingDate IN(CURDATE(),CURDATE()+interval 1 Day);
这将产生以下输出 −
+--------------+ | CustomerName | +--------------+ | David | | Robert | +--------------+ 2 rows in set (0.00 sec)
