使用 date() 函数匹配日期来更新 MySQL 表列?
mysqlmysqli database更新于 2023/11/5 21:29:00
以下是使用 date() 函数匹配日期并更新列的语法 −
update yourTableName set yourColumnName=yourValue where date(yourColumnName)=curdate();
首先我们创建一个表 −
mysql> create table DemoTable1816 ( Name varchar(20), JoiningDate datetime ); Query OK, 0 rows affected (0.00 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable1816 values('Chris','2019-11-29 12:34:50');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1816 values('David','2019-11-30 11:00:00');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1816 values('Mike','2018-11-30 10:20:30');
Query OK, 1 row affected (0.00 sec)
使用 select 语句显示表中的所有记录 −
mysql> select * from DemoTable1816;
这将产生以下输出 −
+-------+---------------------+ | Name | JoiningDate | +-------+---------------------+ | Chris | 2019-11-29 12:34:50 | | David | 2019-11-30 11:00:00 | | Mike | 2018-11-30 10:20:30 | +-------+---------------------+ 3 rows in set (0.00 sec)
这是通过匹配日期来更新列的查询 −
mysql> update DemoTable1816 set Name='Robert' where date(JoiningDate)=curdate(); Query OK, 1 row affected (0.00 sec) Rows matched: 1 Changed: 1 Warnings: 0
让我们再次检查表记录 −
mysql> select * from DemoTable1816;
这将产生以下输出 −
+--------+---------------------+ | Name | JoiningDate | +--------+---------------------+ | Chris | 2019-11-29 12:34:50 | | Robert | 2019-11-30 11:00:00 | | Mike | 2018-11-30 10:20:30 | +--------+---------------------+ 3 rows in set (0.00 sec)
